1 条题解
- 
  1
C++ :
#include <bits/stdc++.h> using namespace std; int inv[100010]; int C(int n, int m) { int ans = 1; inv[1] = 1; for (int i = 2; i <= m; i++) inv[i] = ((10007 - 10007 / i) * inv[10007 % i]) % 10007, ans = (ans * inv[i]) % 10007; for (int i = n; i > n - m; i--) ans = (ans * i) % 10007; return ans; } int pow(int a, int b) { a %= 10007; int res = 1; while (b) { if (b & 1) res = (res * a) % 10007; a = (a * a) % 10007, b >>= 1; } return res; } int main() { int a, b, k, n, m; cin >> a >> b >> k >> n >> m; cout << ((pow(a, n) * pow(b, m)) % 10007 * C(k, n)) % 10007; return 0; } 
信息
- ID
 - 2842
 - 时间
 - 1000ms
 - 内存
 - 128MiB
 - 难度
 - (无)
 - 标签
 - 递交数
 - 0
 - 已通过
 - 0
 - 上传者