1 条题解

  • 0
    @ 2023-6-11 12:24:29

    C :

    #include<stdio.h>
    int main()
    {
    	int a[100][100];
    	int n,m,i,j,max=0;
    	scanf("%d %d",&n,&m);
    	for(i=0;i<n;i++){
    		for(j=0;j<m;j++){
    			scanf("%d",&a[i][j]);
    		}	
    	}
    	for(i=0;i<n;i++){
    		for(j=0;j<m;j++){
    			if(a[i][j]>max) max=a[i][j];
    		}
    		printf("%d\n",max);
    		max=0;
    	}
    	return 0;
     } 
    

    C++ :

    #include <bits/stdc++.h>
    using namespace std;
    
    int a[110][110];
    int n,m,ma;
    
    int main() {
    	cin>>n>>m;
    	for(int i = 1;i <= n;i++){
    		ma = INT_MIN;
    		for(int j = 1;j <= m;j++){
    			cin>>a[i][j];
    			ma = max(ma,a[i][j]);
    		}
    		cout<<ma<<endl;
    	}
    	return 0;
    }
    
    
    

    Java :

    
    import java.util.Scanner;
    public class Main {
        public static void main(String[] args) {
            Scanner scanner = new Scanner(System.in);
            int num1 = scanner.nextInt();
            int num2 = scanner.nextInt();
            int[][] a = new int[num1][num2];
    //        int[][] b = new int[num1][num2];
            for (int i = 0; i < num1; i++) {
                for(int j = 0;j < num2;j++)
                a[i][j] = scanner.nextInt();
            }
            for (int i = 0; i < num1; i++) {
                System.out.println(MAX(a[i]));
            }
    
    
    
    
    
    
    
        }public static void paiXu(int[] a,int length){
            int temp;
            for(int i = 0;i < length - 1;i++){
                for(int k = 0;k < length - i - 1;k++){
                    if(a[k] > a[k + 1]){
                        temp = a[k];
                        a[k] = a[k + 1];
                        a[k + 1] = temp;
                    }
                }
            }
        } public static void paiXud(int[] a){
            int temp;
            for(int i = 0;i < a.length - 1;i++){
                for(int k = 0;k < a.length - i - 1;k++){
                    if(a[k] < a[k + 1]){
                        temp = a[k];
                        a[k] = a[k + 1];
                        a[k + 1] = temp;
                    }
                }
            }
        } public static void paiXux(int[] a){
            int temp;
            for(int i = 0;i < a.length - 1;i++){
                for(int k = 0;k < a.length - i - 1;k++){
                    if(a[k] > a[k + 1]){
                        temp = a[k];
                        a[k] = a[k + 1];
                        a[k + 1] = temp;
                    }
                }
            }
        }
    
        public static int MAX2(int[][] a){
            int max = a[0][0];
            for (int i = 0; i < a.length; i++) {
                for(int j = 0;j < a[0].length;j++){
                    if(max < a[i][j])max = a[i][j];
                }
            }
            return max;
        }public static int MIN2(int[][] a){
            int min = a[0][0];
            for (int i = 0; i < a.length; i++) {
                for(int j = 0;j < a[0].length;j++){
                    if(min > a[i][j])min = a[i][j];
                }
            }
            return min;
        }
        public static int MAX(int[] a){
            int max = a[0];
            for (int i = 0; i < a.length; i++) {
                if(max < a[i]){
                    max = a[i];
                }
            }
            return max;
        }
    
        public static int MIN(int[] a){
            int min = a[0];
            for (int i = 0; i < a.length; i++) {
                if(min > a[i]){
                   min = a[i];
                }
            }
            return min;
        }
        public static int sum(int a){
            int x,s = 0;
            while(a != 0){
                x = a % 10;
                s = s + x;
                a /= 10;
            }
            return s;
        }
        public static boolean isPrime(int a){
            if(a <= 1)return false;
            else
            for(int i = 2;i <= Math.sqrt(a);i++){
                if(a % i == 0)return false;
            }return true;
        }
    
        public static long qiuYu(long i){
            long a;
            a = i % 10;
            return a;
        }
        public static int daoXu(int x){
            int s = 0,m;
            while(x != 0){
                m = x % 10;
                s = s * 10 + m;
                x /= 10;
            }
            return s;
        }
    
        public static int jiaWei(int x){
            int s = 0,m;
            while(x != 0){
                m = x % 10;
                s = s + m;
                x /= 10;
            }
            return s;
        }
    
        public static int fun(int x){
            if(x == 1 || x == 2)return 1;
            else return fun(x - 1) + fun(x - 2);
        }
    }
    

    Python :

    n,m=list(map(int,input().split()))
    a=list()
    b=list()
    for i in range(n):
        a.append(list(map(int,input().split())))
        print(max(a[i]))
    
    
    
    
    
    • 1

    信息

    ID
    2814
    时间
    1000ms
    内存
    64MiB
    难度
    (无)
    标签
    递交数
    0
    已通过
    0
    上传者