1 条题解
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0
C :
#include <stdio.h> int ax[10000]; int ay[10000]; int main() { int x,y; scanf("%d %d",&x,&y); int i; int jx=0,jy=0; int sumx=0,sumy=0; //分别求x和y的所有约数 for(i=1; i<=x/2; i++) { if(x%i==0) { ax[jx]=i; jx++; } } for(i=1; i<=y/2; i++) { if(y%i==0) { ay[jy]=i; jy++; } } //求两个数的约数和 for(i=0; i<jx; i++) sumx+=ax[i]; for(i=0; i<jy; i++) sumy+=ay[i]; if(sumx==y&&sumy==x) printf("yes\n"); else printf("no\n"); return 0; }
C++ :
#include<iostream> #include<cmath> using namespace std; long long a,b,gsa=0,gsb=0; int main() { cin>>a>>b; for(int i=1; i<a; i++) { if(a%i==0) gsa+=i; } for(int i=1; i<b; i++) { if(b%i==0) gsb+=i; } if(gsa==b && gsb==a) cout<<"yes"; else cout<<"no"; return 0; }
Java :
import java.util.Scanner; public class Main { public static void main(String[] args) { Scanner scanner = new Scanner(System.in); int a = scanner.nextInt(); int b = scanner.nextInt(); int s1 = 0,s2 = 0; for(int i = 1;i < a;i++){ if(a % i == 0)s1 = s1 + i; } for(int i = 1;i < b;i++){ if(b % i == 0)s2 = s2 + i; } if(s1 == b || s2 == a) System.out.println("yes"); else System.out.println("no"); }public static void paiXu(int[] a,int length){ int temp; for(int i = 0;i < length - 1;i++){ for(int k = 0;k < length - i - 1;k++){ if(a[k] > a[k + 1]){ temp = a[k]; a[k] = a[k + 1]; a[k + 1] = temp; } } } } public static void paiXud(int[] a){ int temp; for(int i = 0;i < a.length - 1;i++){ for(int k = 0;k < a.length - i - 1;k++){ if(a[k] < a[k + 1]){ temp = a[k]; a[k] = a[k + 1]; a[k + 1] = temp; } } } } public static void paiXux(int[] a){ int temp; for(int i = 0;i < a.length - 1;i++){ for(int k = 0;k < a.length - i - 1;k++){ if(a[k] > a[k + 1]){ temp = a[k]; a[k] = a[k + 1]; a[k + 1] = temp; } } } } public static int MAX(int[] a){ int max = a[0]; for (int i = 0; i < a.length; i++) { if(max < a[i]){ max = a[i]; } } return max; } public static int MIN(int[] a){ int min = a[0]; for (int i = 0; i < a.length; i++) { if(min > a[i]){ min = a[i]; } } return min; } public static int sum(int a){ int x,s = 0; while(a != 0){ x = a % 10; s = s + x; a /= 10; } return s; } public static boolean isPrime(int a){ if(a <= 1)return false; else for(int i = 2;i <= Math.sqrt(a);i++){ if(a % i == 0)return false; }return true; } public static long qiuYu(long i){ long a; a = i % 10; return a; } public static int daoXu(int x){ int s = 0,m; while(x != 0){ m = x % 10; s = s * 10 + x; x /= 10; } return s; } public static int jiaWei(int x){ int s = 0,m; while(x != 0){ m = x % 10; s = s + m; x /= 10; } return s; } }
Python :
def qh(n): s=0 for i in range(1,n//2+1): if(n%i==0): s=s+i return(s) sr=input().split() n1=int(sr[0]) n2=int(sr[1]) s1=qh(n1) s2=qh(n2) if(s1==n2 and s2==n1): print("yes") else: print("no")
- 1
信息
- ID
- 2732
- 时间
- 1000ms
- 内存
- 512MiB
- 难度
- (无)
- 标签
- 递交数
- 0
- 已通过
- 0
- 上传者