1 条题解
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0
C++ :
#include <iostream> #include <fstream> #include <string> #include <cmath> using namespace std; const int maxn = 200; char seq[maxn] = {'A','B','C','D','E','F','G','H','I','J','K','L','M','N','O','P','Q','R','S','T','U','V','W','X','Y','Z'}; char print_seq[maxn][maxn]; int n; void f(int idx, int len, int x, int y){ if(idx == -1){ return ; } for(int dx = -(len); dx <= (len); dx += len ){ for(int dy = -(len); dy <= (len); dy += len){ int xx = x + dx; int yy = y + dy; print_seq[xx][yy] = seq[idx]; } } f(idx - 1, len + 1, x, y); } int main(){ // fstream cin("a.txt"); cin>>n; for(int i = 0; i < (2 * n - 1); ++i){ for(int j = 0; j < (2 * n - 1); ++j){ print_seq[i][j] = '.'; } } f(n - 2, 1, n - 1, n - 1); print_seq[n - 1][n - 1] = seq[n - 1]; for(int i = 0; i < (2 * n - 1); ++i){ for(int j = 0; j < (2 * n - 1); ++j){ cout<<print_seq[i][j]; } cout<<endl; } return 0; }
Java :
import java.util.Scanner; public class Main { public static void main(String[] args) { Scanner sc = new Scanner(System.in); //接收用户输入的“边长” n = sc.nextInt(); //如果边长为1,直接输出得了 if(n == 1){ System.out.println("A"); return; } int b = n*2-1; char arr[][] = new char[b][b]; for(int i = 0; i < b; i++){ for(int j = 0; j < b; j++){ arr[i][j] = '.'; } } f(arr, b); //打印结果图像 for(int i = 0; i < b; i++){ for(int j = 0; j < b; j++){ System.out.print(arr[i][j]); } System.out.println(); } } static int n; static void f(char ch[][], int b){ int start = 0; int end = b-1; char w= 'A'; int add = b/3+n/3; int cnt = 0; while(true){ //由外向内 for(int i = start; i <= end; i+=add){ ch[i][start] = w;//左 ch[start][i] = w;//上 ch[i][end] = w;//右 ch[end][i] = w;//下 } start++; end--; w++; add = add - 1; if(add <= 0)add =1; cnt++; if(cnt == n)break; } } }
- 1
信息
- ID
- 2726
- 时间
- 1000ms
- 内存
- 512MiB
- 难度
- (无)
- 标签
- 递交数
- 0
- 已通过
- 0
- 上传者