1 条题解
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0
C :
#include<stdio.h> #define max(x,y) ((x)>(y)?(x):(y)) #define min(x,y) ((x)<(y)?(x):(y)) int main(){ double x1,y1,x2,y2; //矩形1 double x3,y3,x4,y4; //矩形2 double m1,n1; //交集左上角坐标. double m2,n2; //交集右下角坐标. scanf("%lf%lf%lf%lf",&x1,&y1,&x2,&y2); scanf("%lf%lf%lf%lf",&x3,&y3,&x4,&y4); m1 = max(min(x1,x2),min(x3,x4)); n1 = max(min(y1,y2),min(y3,y4)); m2 = min(max(x1,x2),max(x3,x4)); n2 = min(max(y1,y2),max(y3,y4)); if(m2>m1 && n2>n1) printf("%.2f\n",(m2 - m1)*(n2 - n1)); else printf("0.00\n"); return 0; }
C++ :
#include<bits/stdc++.h> using namespace std; int main(){ double x1,y1,x2,y2; double x3,y3,x4,y4; double m1,n1; //交集左上角坐标. double m2,n2; //交集右下角坐标. cin>>x1>>y1>>x2>>y2; cin>>x3>>y3>>x4>>y4; m1 = max(min(x1,x2),min(x3,x4)); n1 = max(min(y1,y2),min(y3,y4)); m2 = min(max(x1,x2),max(x3,x4)); n2 = min(max(y1,y2),max(y3,y4)); cout<<fixed<<setprecision(2); if(m2>m1 && n2>n1) cout<<(m2 - m1)*(n2 - n1); else cout<<0.0; return 0; }
- 1
信息
- ID
- 2704
- 时间
- 1000ms
- 内存
- 512MiB
- 难度
- (无)
- 标签
- 递交数
- 0
- 已通过
- 0
- 上传者