1 条题解

  • 0
    @ 2023-6-11 12:21:11

    C++ :

    #include <bits/stdc++.h>
    using namespace std;
    int main(){
        int n,a[110],i;
        cin>>n;
        for(i = 1;i <= n;i++){
        	cin>>a[i];
    	}
    	int x = a[2] - a[1];
    	double y = a[2] * 1.0 / a[1];
    	int dc = 1;
    	int db = 1;
    	for(i = 3;i <= n;i++){
    		if(a[i]-a[i-1] != x){
    			dc = 0;
    		}
    		
    		if(a[i] * 1.0 / a[i-1] != y){
    			db = 0;
    		}
    	}
    	
    	if(dc == 1) cout<<"dengcha";
    	else if(db == 1) cout<<"dengbi";
    	else cout<<"no";
        return 0;
    }
    

    Java :

    
    import java.util.Scanner;
    public class Main {
        public static void main(String[] args) {
            Scanner scanner = new Scanner(System.in);
            int num1 = scanner.nextInt();
            int[] count = new int[80];
            int[] a = new int[num1];
            for (int i = 0; i < num1; i++) {
                a[i] = scanner.nextInt();
            }
            for (int i = 0; i < num1 - 2; i++) {
                if(a[i] >= a[i+1]){
                    if(a[i] % a[i+1] != a[i+1] % a[i+2] && a[i] - a[i+1] != a[i+1] - a[i+2]){
                        System.out.println("no");
                        break;
                    }
                }else if(a[i] < a[i+1]){
                    if(a[i+2] % a[i+1] != a[i+1] % a[i] && (a[i] - a[i+1] != a[i+1] - a[i+2])){
                        System.out.println("no");break;
                    }
                }
                if(i == num1 - 3){
                    if(a[i] - a[i+1] == a[i+1] - a[i+2]) System.out.println("dengcha");
                    else if(a[i] >= a[i+1] && a[i] % a[i+1] == a[i+1] % a[i+2]) System.out.println("dengbi");
                    else if(a[i] < a[i+1] && a[i+2] % a[i+1] == a[i+1] % a[i]) System.out.println("dengbi");
                }
            }
    
    
    
    
    
        }public static void paiXu(int[] a,int length){
            int temp;
            for(int i = 0;i < length - 1;i++){
                for(int k = 0;k < length - i - 1;k++){
                    if(a[k] > a[k + 1]){
                        temp = a[k];
                        a[k] = a[k + 1];
                        a[k + 1] = temp;
                    }
                }
            }
        } public static void paiXud(int[] a){
            int temp;
            for(int i = 0;i < a.length - 1;i++){
                for(int k = 0;k < a.length - i - 1;k++){
                    if(a[k] < a[k + 1]){
                        temp = a[k];
                        a[k] = a[k + 1];
                        a[k + 1] = temp;
                    }
                }
            }
        } public static void paiXux(int[] a){
            int temp;
            for(int i = 0;i < a.length - 1;i++){
                for(int k = 0;k < a.length - i - 1;k++){
                    if(a[k] > a[k + 1]){
                        temp = a[k];
                        a[k] = a[k + 1];
                        a[k + 1] = temp;
                    }
                }
            }
        }
    
        public static int MAX(int[] a){
            int max = a[0];
            for (int i = 0; i < a.length; i++) {
                if(max < a[i]){
                    max = a[i];
                }
            }
            return max;
        }
    
        public static int MIN(int[] a){
            int min = a[0];
            for (int i = 0; i < a.length; i++) {
                if(min > a[i]){
                   min = a[i];
                }
            }
            return min;
        }
        public static int sum(int a){
            int x,s = 0;
            while(a != 0){
                x = a % 10;
                s = s + x;
                a /= 10;
            }
            return s;
        }
        public static boolean isPrime(int a){
            if(a <= 1)return false;
            else
            for(int i = 2;i <= Math.sqrt(a);i++){
                if(a % i == 0)return false;
            }return true;
        }
    
        public static long qiuYu(long i){
            long a;
            a = i % 10;
            return a;
        }
    }
    

    Python :

    n=int(input())
    a=list(map(int,input().split()))
    d1=a[1]-a[0]
    d2=a[1]/a[0]
    f1=0
    f2=0
    for i in range(2,n):
        if ((a[i]-a[i-1])!=d1):
            f1=1
        if((a[i]/a[i-1])!=d2):
            f2=1
    if(f1==0):
        print("dengcha")
    elif(f2==0):
        print("dengbi")
    else:
        print("no")
    
    • 1

    信息

    ID
    2693
    时间
    1000ms
    内存
    64MiB
    难度
    (无)
    标签
    递交数
    0
    已通过
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