1 条题解
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0
C++ :
#include <bits/stdc++.h> using namespace std; int main(){ int n,a[110],i; cin>>n; for(i = 1;i <= n;i++){ cin>>a[i]; } int f1 = 1;//假设递增 int f2 = 1;//假设递减 for(i = 1;i < n;i++){ if(a[i] > a[i+1]){ f1 = 0; } if(a[i] < a[i+1]){ f2 = 0; } } if(f1 == 0 && f2 == 0){ cout<<"No"; }else{ cout<<"Good"; } return 0; }
Java :
import java.util.Scanner; public class Main { public static void main(String[] args) { Scanner scanner = new Scanner(System.in); int num1 = scanner.nextInt(); int[] count = new int[80]; int[] a = new int[num1]; int[] b = new int[num1]; int[] c = new int[num1]; for (int i = 0; i < num1; i++) { c[i] = b[i] = a[i] = scanner.nextInt(); } int flag1 = 0,flag2 = 2; paiXux(a); paiXud(b); for (int i = 0; i < num1; i++) { if(c[i] != a[i]){ flag1 = 1; break; } } for (int i = 0; i < num1; i++) { if(c[i] != b[i]){ flag2 = 1; break; } } if(flag1 == 0 || flag2 == 2) System.out.println("Good"); else System.out.println("No"); }public static void paiXu(int[] a,int length){ int temp; for(int i = 0;i < length - 1;i++){ for(int k = 0;k < length - i - 1;k++){ if(a[k] > a[k + 1]){ temp = a[k]; a[k] = a[k + 1]; a[k + 1] = temp; } } } } public static void paiXud(int[] a){ int temp; for(int i = 0;i < a.length - 1;i++){ for(int k = 0;k < a.length - i - 1;k++){ if(a[k] < a[k + 1]){ temp = a[k]; a[k] = a[k + 1]; a[k + 1] = temp; } } } } public static void paiXux(int[] a){ int temp; for(int i = 0;i < a.length - 1;i++){ for(int k = 0;k < a.length - i - 1;k++){ if(a[k] > a[k + 1]){ temp = a[k]; a[k] = a[k + 1]; a[k + 1] = temp; } } } } public static int MAX(int[] a){ int max = a[0]; for (int i = 0; i < a.length; i++) { if(max < a[i]){ max = a[i]; } } return max; } public static int MIN(int[] a){ int min = a[0]; for (int i = 0; i < a.length; i++) { if(min > a[i]){ min = a[i]; } } return min; } public static int sum(int a){ int x,s = 0; while(a != 0){ x = a % 10; s = s + x; a /= 10; } return s; } public static boolean isPrime(int a){ if(a <= 1)return false; else for(int i = 2;i <= Math.sqrt(a);i++){ if(a % i == 0)return false; }return true; } public static long qiuYu(long i){ long a; a = i % 10; return a; } }
Python :
n=int(input()) a=list(map(int,input().split())) b=sorted(a) c=[] for i in range(n-1,-1,-1): c.append(b[i]) if (a==b or c==a): print("Good") else: print("No")
- 1
信息
- ID
- 2692
- 时间
- 1000ms
- 内存
- 64MiB
- 难度
- (无)
- 标签
- 递交数
- 0
- 已通过
- 0
- 上传者