1 条题解

  • 0
    @ 2023-6-11 12:20:56

    C :

    #include<stdio.h>
    int main()
    {
        int i;
        int n;
        scanf("%d",&n);
        for(i=1000;i<=n;i++)
        {
            if(i%2==1)
            {
                if(i/1000==i/10%10&&i/100%10==i%10)
                printf("%d\n",i);
            }
        }
        return 0;
    }
    
    
    

    C++ :

    #include <bits/stdc++.h>;
    using namespace std;
    int main(){
    	int n,i;
    	int q,b,s,g;
    	cin>>n;
    	for(i=1000;i<=n;i++){
    		q=i/1000;
    		b=i/100%10;
    		s=i/10%10;
    		g=i%10;
    		if(q==s&&b==g&&i%2==1){
    			cout<<i<<endl;
    		}
    	}
    }
    

    Java :

    import java.util.Scanner;
    public class Main
    {
        public static void main(String[] args){
           Scanner sc = new Scanner(System.in);     
           int n = sc.nextInt();
           for(int i=1000;i<=n;i++) {
                int a =i/1000;
                int b =i/100%10;
                int c =i/10%10;
                int d =i%10;
                int x =1000*c+100*d+10*a+b;
                if(x==i && i%2==1) {
                	System.out.println(i);
                }
             } 
                
       }
    }
    

    Python :

    n = int(input())
    for i in range(1000, n + 1):
        q = i // 1000 % 10
        b = i // 100 % 10
        s = i // 10 % 10
        g = i // 1 % 10
        if q == s and b == g and i % 2 == 1:
            print(i)
    
    
    • 1

    信息

    ID
    2622
    时间
    1000ms
    内存
    16MiB
    难度
    (无)
    标签
    递交数
    0
    已通过
    0
    上传者