1 条题解

  • 0
    @ 2023-6-11 12:20:42

    C :

    #include<stdio.h>
    int main()
    {
        int m,n,t;
        scanf("%d%d%d",&m,&n,&t);
        if(m>=90||n>=90||t>=90)
            printf("beijing");
        else
            printf("nanjing");
        return 0;
    }
    
    

    C++ :

    #include <bits/stdc++.h>
    using namespace std;
    
    int main(){
        int x,y,z;
        cin>>x>>y>>z;
        if(x >= 90 || y >= 90 || z >= 90){
        	cout<<"beijing";
    	}else{
    		cout<<"nanjing";
    	}
    }
     
    
    

    Java :

    import java.util.Scanner;
    public class Main
    {
    	public static void main(String[] Args)
    	{
    		Scanner sc = new Scanner(System.in);
    		int a = sc.nextInt();
    		int b = sc.nextInt();
    		int c = sc.nextInt();
    		if(a>=90||b>=90||c>=90)
    			System.out.println("beijing");
    		else
    			System.out.println("nanjing");
    	}
    }
    

    Python :

    n = input().split()
    x = int(n[0])
    y = int(n[1])
    z = int(n[2])
    if x >= 90 or y >= 90 or z >= 90:
        print('beijing')
    else:
        print('nanjing')
    
    
    • 1

    【入门】暑期的旅游计划(2)

    信息

    ID
    2584
    时间
    1000ms
    内存
    64MiB
    难度
    (无)
    标签
    递交数
    0
    已通过
    0
    上传者