1 条题解

  • 0
    @ 2023-6-11 12:20:42

    C :

    #include<stdio.h>
    int main()
    {
        double x;
        scanf("%lf",&x);
        if(x<=20)
            printf("%.2lf",1.68*x);
        if(x>20)
            printf("%.2lf",1.98*x);
            return 0;
    }
    
    

    C++ :

    #include<bits/stdc++.h>
    using namespace std;
    int main(){
    	double q,n;
    	cin>>n;
    	if(n<=20) q=n*1.68;
    	else q=n*1.98;
    	cout<<fixed<<setprecision(2)<<q<<endl;
    	return 0;
    }
    
    

    Java :

    import java.util.Scanner;
    
    public class Main {
    
    	public static void main(String[] args) {
    		// TODO Auto-generated method stub
    		Scanner sc = new Scanner(System.in);
    		double a = sc.nextDouble();
    		double s;
    		if(a<=20){
    			s = (double)(a * 1.68);
    			System.out.println(String.format("%.2f", s));
    		}else if(a > 20){
    			s = (double)(a * 1.98);
    			System.out.println(String.format("%.2f", s));
    		}
    		sc.close();
    	}
    
    }
    

    Python :

    n = float(input())
    if n <= 20:
        m = n * 1.68
    else:
        m = n * 1.98
    print('%.2f' % m)
    
    
    • 1

    信息

    ID
    2575
    时间
    1000ms
    内存
    16MiB
    难度
    (无)
    标签
    递交数
    0
    已通过
    0
    上传者