1 条题解

  • 0
    @ 2023-6-11 12:20:41

    C :

    #include<stdio.h>
    
    void main(){
    	int n;
    	double p;
    	scanf("%d",&n);
    	
    	if(n<10&&n>0){
    		p=n*1.5;
    	}else if(n>=10){
    		p=n*1.2;
    	}
    	printf("%.1f",p);
    }
    

    C++ :

    #include <bits/stdc++.h>
    using namespace std;
    
    int main(){
        int n;
        cin>>n;
    	double r;
    	if(n < 10){
    		r = n * 1.5;
    	}else{
    		r = n * 1.2;
    	}
    	
    	cout<<fixed<<setprecision(1)<<r;
    }
     
    
    

    Java :

    import java.util.Scanner;
    
    public class Main {
    
    	public static void main(String[] args) {
    		// TODO Auto-generated method stub
    		Scanner sc = new Scanner(System.in);
    		int n = sc.nextInt();
    		double s;
    		if(n < 10){
    			s =(double)(n * 1.5);
    			System.out.println(String.format("%.1f", s));
    		}else if(n >= 10){
    			s =(double)(n * 1.2);
    			System.out.println(String.format("%.1f", s));
    		}
    	}
    
    }
    

    Python :

    n = int(input())
    if n < 10:
        print('%.1f' % (n * 1.5))
    if n >= 10:
        print('%.1f' % (n * 1.2))
    
    
    • 1

    信息

    ID
    2570
    时间
    1000ms
    内存
    64MiB
    难度
    (无)
    标签
    递交数
    0
    已通过
    0
    上传者