1 条题解
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0
C :
#include<stdio.h> int main() { double m,n,t,s; scanf("%lf%lf%lf",&n,&m,&t); s=m+n+t; if(s>=200) printf("%.1lf",s*0.8); else printf("%.1lf",s*0.9); return 0; }
C++ :
#include <bits/stdc++.h> using namespace std; int main(){ double a,b,c,r; cin>>a>>b>>c; r = a + b + c; if(r >= 200){ r = r * 0.8; }else{ r = r * 0.9; } cout<<fixed<<setprecision(1)<<r; }
Java :
import java.util.Scanner; public class Main { public static void main(String[] args) { // TODO Auto-generated method stub Scanner sc = new Scanner(System.in); double a = sc.nextDouble(); double b = sc.nextDouble(); double c = sc.nextDouble(); double sum; sum = a + b + c; double s; if(sum < 200){ s = sum * 0.9; System.out.println(String.format("%.1f", s)); }else if(sum >= 200){ s = sum * 0.8; System.out.println(String.format("%.1f", s)); } } }
Python :
n = input().split() a = float(n[0]) b = float(n[1]) c = float(n[2]) su = a + b + c if su >= 200: print("%.1f" % (su * 0.8)) else: print('%.1f' % (su * 0.9))
- 1
信息
- ID
- 2569
- 时间
- 1000ms
- 内存
- 128MiB
- 难度
- (无)
- 标签
- 递交数
- 0
- 已通过
- 0
- 上传者