1 条题解

  • 0
    @ 2023-6-11 12:20:40

    C :

    #include<stdio.h>
    int main()
    {
        int m,n,t,a,b,c,d;
        scanf("%d",&m);
        n=m/100000;
        t=m%10;
        a=m/10000%10;
        b=m/10%10;
        c=m/1000%10;
        d=m/100%10;
        if(n==t&&a==b&&c==d)
            printf("Y");
        else
            printf("N");
        return 0;
    }
    

    C++ :

    #include <bits/stdc++.h>
    using namespace std;
    
    int main(){
        int n,g,s,b,q,w,sw;
        cin>>n;
        sw = n / 100000;
        w = n / 10000 % 10;
        q = n / 1000 % 10;
        b = n / 100 % 10;
        s = n / 10 % 10;
        g = n % 10;
        
        if(sw == g && w == s && q == b){
        	cout<<"Y";
    	}else{
    		cout<<"N";
    	}
    }
     
    
    

    Java :

    import java.util.Scanner;
    
    public class Main {
    
    	public static void main(String[] args) {
    		// TODO Auto-generated method stub
    		Scanner sc = new Scanner(System.in);
    		int n = sc.nextInt();
    		int g = n % 10;
    		int s = n / 10 % 10;
    		int b = n / 100 % 10;
    		int q = n / 1000 % 10;
    		int w = n / 10000 % 10;
    		int sw = n / 100000;
    		if(g==sw && s==w && b==q){
    			System.out.println("Y");
    		}else{
    			System.out.println("N");
    		}
    	}
    
    }
    

    Python :

    x = int(input())
    a = x//100000
    b = x//10000%10
    c = x//1000%10
    y = 100000*a + 10000*b + 1000*c + 100*c + 10*b + a
    if y == x:
        print('Y')
    else:
        print('N')
    
    • 1

    信息

    ID
    2538
    时间
    1000ms
    内存
    64MiB
    难度
    (无)
    标签
    递交数
    0
    已通过
    0
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