1 条题解
-
0
C :
#include<stdio.h> void main(){ int x; double p; scanf("%d",&x); p=0.9*x; printf("%.1f",p); }
C++ :
#include<bits/stdc++.h> using namespace std; int main() { int n; cin>>n; cout<<fixed<<setprecision(1)<<(n+n*0.8+n*0.9) / 3; }
Java :
import java.util.Scanner; public class Main { public static void main(String[] args) { Scanner sc = new Scanner(System.in); double x = sc.nextDouble(); double a = x * 0.8; double b = x * 0.9; double p =(double) (x + a + b) / 3; System.out.println(String.format("%.1f", p)); } }
Python :
a=int(input()) b=a*0.8 c=a*0.9 print("%.1lf"%((a+b+c)/3))
- 1
信息
- ID
- 2525
- 时间
- 1000ms
- 内存
- 64MiB
- 难度
- (无)
- 标签
- 递交数
- 0
- 已通过
- 0
- 上传者