1 条题解

  • 0
    @ 2023-6-11 12:20:39

    C :

    #include<stdio.h>
    int main()
    {
    	int a;
    	scanf("%d",&a);
    	printf("%d\n%.1f",a/100+a%100,(a/100)*1.0/(a%100));
    	return 0;
    }
    

    C++ :

    #include <iostream>
    #include <iomanip>
    using namespace std;
    
    int main(){
    	int n,g,s,b,q;
    	cin>>n;
    	q = n / 1000;
    	b = n / 100 % 10;
    	s = n / 10 % 10;
    	g = n % 10;
    	cout<<q*10+b+s*10+g<<endl;
    	cout<<fixed<<setprecision(1)<<(q*10+b)*1.0/(s*10+g);
    }
    
    
    

    Java :

    import java.util.Scanner;
    
    public class Main {
    	 
        /**
         * @param args
         */
    	public static void main(String[] args) {
    		Scanner sc = new Scanner(System.in);
    		int a = sc.nextInt();
    		int g = a%10;
    		int s = a/10 %10;
    		int b = a/100 %10;
    		int q = a/1000;
    		int x = b + q*10;
    		int y = g + s*10;
    		System.out.println(x+y);
    		System.out.println(String.format("%.1f", (double)x/y));
    	}
    	public static void printArr(int [] a){
    		for (int i = 0 ;i<= a.length - 1 ;i++) {
    			System.out.print( a[i] + " ");
    		}
    	}
    }
    

    Python :

    n = int(input())
    q = n // 1000 % 10
    b = n // 100 % 10
    s = n // 10 % 10
    g = n // 1 % 10
    x = q * 10 + b
    y = s * 10 + g
    print(x + y)
    print("%.1f" % (x / y))
    
    • 1

    信息

    ID
    2521
    时间
    1000ms
    内存
    64MiB
    难度
    (无)
    标签
    递交数
    0
    已通过
    0
    上传者