1 条题解
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0
C :
#include<stdio.h> #include<limits.h> int a[1001]; int main(){ int n,i,mi=INT_MAX,mx=INT_MIN; scanf("%d",&n); for(i=1;i<=n;i++){ scanf("%d",&a[i]); } for(i=1;i<=n;i++){ if(a[i]<mi){ mi = a[i]; } if(a[i]>mx){ mx=a[i]; } } for(i=1;i<=n;i++){ if(a[i]==mx){ printf("%d ",a[i]*2); }else if(a[i]==mi){ printf("%d ",a[i]+1); }else{ printf("%d ",a[i]); } } return 0; }
C++ :
#include<bits/stdc++.h> using namespace std; int main() { int a[1010],n,i,ma,mi; cin>>n; for(i = 0;i < n;i++){ cin>>a[i]; } ma = a[0]; mi = a[0]; for(i = 1;i < n;i++){ if(a[i] > ma){ ma = a[i]; } if(a[i] < mi){ mi = a[i]; } } for(i = 0;i < n;i++){ if(a[i] == ma){ a[i] = a[i] * 2; }else if(a[i] == mi){ a[i] = a[i] + 1; } } for(i = 0;i < n;i++){ cout<<a[i]<<" "; } return 0; }
Java :
import java.util.Scanner; public class Main { public static void main(String[] args) { Scanner scanner = new Scanner(System.in); int num1 = scanner.nextInt(); // int num2 = scanner.nextInt(); int[] a = new int[num1]; double s = 0,avg; for (int i = 0; i < num1; i++) { a[i] = scanner.nextInt(); } int m = MAX(a); for (int i = 0; i < num1; i++) { if(m == a[i]){ a[i] = a[i] * 2; }else if(MIN(a) == a[i]) a[i] = a[i] + 1; } for (int i = 0; i < num1; i++) { System.out.print(a[i] + " "); } } public static boolean judge(int i,int j){ int a,s = 0; while(i != 0){ a = i % 10; s = s + a; i /= 10; } if(s == j)return true; else return false; } public static void paiXu(int[] a){ int temp; for(int i = 0;i < a.length - 1;i++){ for(int k = 0;k < a.length - i - 1;k++){ if(a[k] > a[k + 1]){ temp = a[k]; a[k] = a[k + 1]; a[k + 1] = temp; } } } } public static int MAX(int[] a){ int max = a[0]; for (int i = 0; i < a.length; i++) { if(max < a[i]){ max = a[i]; } } return max; } public static int MIN(int[] a){ int min = a[0]; for (int i = 0; i < a.length; i++) { if(min > a[i]){ min = a[i]; } } return min; } }
Python :
# 接收输入整数n n = int(input()) # n个数字放入字符串列表m中 m = input().split() # 字符串列表转换为整型列表 for i in range(0, n): m[i] = int(m[i]) # 求列表中最大值mx mx = max(m) mi = min(m) for i in range(0, n): if m[i] == mx: m[i] = 2 * mx if m[i] == mi: m[i] = mi + 1 #循环列表,输出最终数字 for i in range(0, n): print(m[i], end=' ')
- 1
信息
- ID
- 2496
- 时间
- 1000ms
- 内存
- 128MiB
- 难度
- (无)
- 标签
- 递交数
- 0
- 已通过
- 0
- 上传者