1 条题解
-
0
C++ :
#include <bits/stdc++.h> using namespace std; int main(){ int n; char s; cin>>n; int c = 0;//计数器 int m = 0;//最多出现的次数 int i; for(i = 0;i < n;i++){ cin>>s; if(s == 'A'){ c++; if(c > m){ m = c; } }else{ c = 0; } } cout<<m<<endl; return 0; }
Java :
import java.util.Scanner; public class Main { public static void main(String[] args) { Scanner scanner = new Scanner(System.in); int num1 = scanner.nextInt(); String str = new String(); int[] b = new int[num1]; int[] count = new int[100]; double avg; int max = 0; int x = 0,m = 0; str = scanner.next(); char a[] = str.toCharArray(); for (int i = 0; i < num1; i++) { if(a[i] == 'A'){ m++; if(max < m)max = m; }else{ m = 0; } } System.out.println(max); } public static boolean judge(int i,int j){ int a,s = 0; while(i != 0){ a = i % 10; s = s + a; i /= 10; } if(s == j)return true; else return false; } public static void paiXux(int[] a){ int temp; for(int i = 0;i < a.length - 1;i++){ for(int k = 0;k < a.length - i - 1;k++){ if(a[k] > a[k + 1]){ temp = a[k]; a[k] = a[k + 1]; a[k + 1] = temp; } } } }public static void paiXu(int[] a,int length){ int temp; for(int i = 0;i < length - 1;i++){ for(int k = 0;k < length - i - 1;k++){ if(a[k] > a[k + 1]){ temp = a[k]; a[k] = a[k + 1]; a[k + 1] = temp; } } } } public static void paiXud(int[] a){ int temp; for(int i = 0;i < a.length - 1;i++){ for(int k = 0;k < a.length - i - 1;k++){ if(a[k] < a[k + 1]){ temp = a[k]; a[k] = a[k + 1]; a[k + 1] = temp; } } } } public static int MAX(int[] a){ int max = a[0]; for (int i = 0; i < a.length; i++) { if(max < a[i]){ max = a[i]; } } return max; } public static int MIN(int[] a){ int min = a[0]; for (int i = 0; i < a.length; i++) { if(min > a[i]){ min = a[i]; } } return min; } public static int sum(int a){ int x,s = 0; while(a != 0){ x = a % 10; s = s + x; a /= 10; } return s; } public static boolean isPrime(int a){ if(a <= 1)return false; else for(int i = 2;i <= Math.sqrt(a);i++){ if(a % i == 0)return false; }return true; } public static int qiuYu(int i){ int a; a = i % 10; return a; } }
Python :
n=int(input()) a=input() da=0 k=0 for i in range(len(a)): x2=a[i:i+1] if(x2=="A"): k=k+1 if(k>da): da=k else: k=0 print(da)
- 1
信息
- ID
- 2460
- 时间
- 1000ms
- 内存
- 128MiB
- 难度
- (无)
- 标签
- 递交数
- 0
- 已通过
- 0
- 上传者