1 条题解

  • 0
    @ 2023-6-11 12:18:08

    C++ :

    #include <bits/stdc++.h>
    using namespace std;
    
    int main(){
    	int n;
    	char s;
    	cin>>n;
    	
    	int c = 0;//计数器
    	int m = 0;//最多出现的次数
    	int i;
    	for(i = 0;i < n;i++){
    		cin>>s;
    		if(s == 'A'){
    			c++;
    			if(c > m){
    				m = c;
    			} 
    		}else{
    			c = 0;
    		}
    	} 
    	
    	cout<<m<<endl;
    	return 0;
    }
    
    
    

    Java :

    import java.util.Scanner;
    public class Main {
        public static void main(String[] args) {
            Scanner scanner = new Scanner(System.in);
            int num1 = scanner.nextInt();
            String str = new String();
            int[] b = new int[num1];
            int[] count = new int[100];
            double avg;
            int max = 0;
            int x = 0,m = 0;
                str = scanner.next();
            char a[] = str.toCharArray();
            for (int i = 0; i < num1; i++) {
                if(a[i] == 'A'){
                    m++;
                    if(max < m)max = m;
                }else{
                    m = 0;
                }
    
            }
            System.out.println(max);
        }
    
        public static boolean judge(int i,int j){
            int a,s = 0;
            while(i != 0){
                a = i % 10;
                s = s + a;
                i /= 10;
            }
            if(s == j)return true;
            else return false;
        }
    
        public static void paiXux(int[] a){
            int temp;
            for(int i = 0;i < a.length - 1;i++){
                for(int k = 0;k < a.length - i - 1;k++){
                    if(a[k] > a[k + 1]){
                        temp = a[k];
                        a[k] = a[k + 1];
                        a[k + 1] = temp;
                    }
                }
            }
        }public static void paiXu(int[] a,int length){
            int temp;
            for(int i = 0;i < length - 1;i++){
                for(int k = 0;k < length - i - 1;k++){
                    if(a[k] > a[k + 1]){
                        temp = a[k];
                        a[k] = a[k + 1];
                        a[k + 1] = temp;
                    }
                }
            }
        } public static void paiXud(int[] a){
            int temp;
            for(int i = 0;i < a.length - 1;i++){
                for(int k = 0;k < a.length - i - 1;k++){
                    if(a[k] < a[k + 1]){
                        temp = a[k];
                        a[k] = a[k + 1];
                        a[k + 1] = temp;
                    }
                }
            }
        }
    
        public static int MAX(int[] a){
            int max = a[0];
            for (int i = 0; i < a.length; i++) {
                if(max < a[i]){
                    max = a[i];
                }
            }
            return max;
        }
    
        public static int MIN(int[] a){
            int min = a[0];
            for (int i = 0; i < a.length; i++) {
                if(min > a[i]){
                   min = a[i];
                }
            }
            return min;
        }
        public static int sum(int a){
            int x,s = 0;
            while(a != 0){
                x = a % 10;
                s = s + x;
                a /= 10;
            }
            return s;
        }
        public static boolean isPrime(int a){
            if(a <= 1)return false;
            else
            for(int i = 2;i <= Math.sqrt(a);i++){
                if(a % i == 0)return false;
            }return true;
        }
    
        public static int qiuYu(int i){
            int a;
            a = i % 10;
            return a;
        }
    }
    
    

    Python :

    n=int(input())
    a=input()
    da=0
    k=0
    for i in range(len(a)):
        x2=a[i:i+1]
        if(x2=="A"):
            k=k+1
            if(k>da):
                da=k
        else:
            k=0
    print(da)
            
    
    • 1

    信息

    ID
    2460
    时间
    1000ms
    内存
    128MiB
    难度
    (无)
    标签
    递交数
    0
    已通过
    0
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