1 条题解
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0
C :
#include<stdio.h> void main(){ int n,i,j,t=1,s=0,f; scanf("%d",&n); f=1; for(i=1;i<=n;i++){ t=t*i; s=s+t*f; f=f*-1; } printf("%d",s); }
C++ :
#include <bits/stdc++.h> using namespace std; int main(){ int n,i,j,f,s = 0,x; f = 1; cin>>n; for(i = 1;i <= n;i++){ x = 1; for(j = 1;j <= i;j++){ x = x * j; } s = s + f * x; f = f * -1; } cout<<s<<endl; }
Java :
import java.util.Scanner; public class Main { public static void main(String[] args) { Scanner sc = new Scanner(System.in); int n = sc.nextInt(); int i,sum1=0,sum2=0; sc.close(); for(i=1;i<=n;i++) { if(i%2==0) { sum1+=jiecheng(i); }else { sum2+=jiecheng(i); } } System.out.println(sum2-sum1); } public static int jiecheng(int n) { int i,s=1; for(i=1;i<=n;i++) { s*=i; }return s; } }
Python :
n = int(input()) s = 0 for i in range(1, n + 1): t = 1 for j in range(1, i + 1): t = t * j if i % 2 == 1: s = s + t else: s = s - t print(s)
- 1
信息
- ID
- 2438
- 时间
- 1000ms
- 内存
- 128MiB
- 难度
- (无)
- 标签
- 递交数
- 0
- 已通过
- 0
- 上传者