1 条题解
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0
C :
#include<stdio.h> void main(){ int a[100][100]; int i,j,n,m,t=0,g,s,b,q; scanf("%d %d",&n,&m); for(i=0;i<n;i++){ for(j=0;j<m;j++){ scanf("%d",&a[i][j]); } } for(i=0;i<n;i++){ for(j=0;j<m;j++){ g=a[i][j]%10; s=a[i][j]/10%10; b=a[i][j]/100%10; q=a[i][j]/1000; if((g+s+b+q)%2!=0){ t++; } } } printf("%d",t); }
C++ :
#include <iostream> using namespace std; int main(){ int a[200][200],i,j,n,m,c = 0,g,s,b,q,w; cin>>n>>m; for(i = 0;i < n;i++){ for(j = 0;j < m;j++){ cin>>a[i][j]; g = a[i][j] % 10; s = a[i][j] / 10 % 10; b = a[i][j] / 100 % 10; q = a[i][j] / 1000; if((g + s + b + q) % 2 == 1){ c++; } } } cout<<c<<endl; }
Java :
import java.util.Scanner; public class Main { public static void main(String[] args) { Scanner scanner = new Scanner(System.in); int num1 = scanner.nextInt(); int num2 = scanner.nextInt(); int[][] a = new int[num1][num2]; int x = 0; for (int i = 0; i < num1; i++) { for(int k = 0;k < num2;k++){ a[i][k] = scanner.nextInt(); if(sum(a[i][k]) % 2 != 0)x++; } } System.out.println(x); }public static void paiXu(int[] a,int length){ int temp; for(int i = 0;i < length - 1;i++){ for(int k = 0;k < length - i - 1;k++){ if(a[k] > a[k + 1]){ temp = a[k]; a[k] = a[k + 1]; a[k + 1] = temp; } } } } public static void paiXud(int[] a){ int temp; for(int i = 0;i < a.length - 1;i++){ for(int k = 0;k < a.length - i - 1;k++){ if(a[k] < a[k + 1]){ temp = a[k]; a[k] = a[k + 1]; a[k + 1] = temp; } } } } public static void paiXux(int[] a){ int temp; for(int i = 0;i < a.length - 1;i++){ for(int k = 0;k < a.length - i - 1;k++){ if(a[k] > a[k + 1]){ temp = a[k]; a[k] = a[k + 1]; a[k + 1] = temp; } } } } public static int MAX2(int[][] a){ int max = a[0][0]; for (int i = 0; i < a.length; i++) { for(int j = 0;j < a[0].length;j++){ if(max < a[i][j])max = a[i][j]; } } return max; }public static int MIN2(int[][] a){ int min = a[0][0]; for (int i = 0; i < a.length; i++) { for(int j = 0;j < a[0].length;j++){ if(min > a[i][j])min = a[i][j]; } } return min; } public static int MAX(int[] a){ int max = a[0]; for (int i = 0; i < a.length; i++) { if(max < a[i]){ max = a[i]; } } return max; } public static int MIN(int[] a){ int min = a[0]; for (int i = 0; i < a.length; i++) { if(min > a[i]){ min = a[i]; } } return min; } public static int sum(int a){ int x,s = 0; while(a != 0){ x = a % 10; s = s + x; a /= 10; } return s; } public static boolean isPrime(int a){ if(a <= 1)return false; else for(int i = 2;i <= Math.sqrt(a);i++){ if(a % i == 0)return false; }return true; } public static long qiuYu(long i){ long a; a = i % 10; return a; } public static int daoXu(int x){ int s = 0,m; while(x != 0){ m = x % 10; s = s * 10 + x; x /= 10; } return s; } public static int jiaWei(int x){ int s = 0,m; while(x != 0){ m = x % 10; s = s + m; x /= 10; } return s; } public static int fun(int x){ if(x == 1 || x == 2)return 1; else return fun(x - 1) + fun(x - 2); } }
Python :
#定义一个数求各位数字之和的函数 def cw(x): su = 0 # 短除法拆位,求拆位后各位的和su while x > 0: su += x % 10 x //= 10 return su s = input().split() # 行数n n = int(s[0]) # 列数m m = int(s[1]) c = 0 a = [[0 for j in range(m)] for i in range(n)] #循环接收输入 for i in range(n): t = input().split() for j in range(m): a[i][j] = int(t[j]) #循环遍历二维数组 for i in range(n): for j in range(m): if cw(a[i][j]) % 2 != 0: c += 1 print(c)
- 1
信息
- ID
- 2416
- 时间
- 1000ms
- 内存
- 128MiB
- 难度
- (无)
- 标签
- 递交数
- 0
- 已通过
- 0
- 上传者