1 条题解

  • 0
    @ 2023-6-11 12:17:13

    C :

    #include<stdio.h>
    int main(){
    	int i,j,n;
    	scanf("%d",&n);
    	for(i=1;i<=n;i++){
    		for(j=1;j<=n-i;j++){
    			printf("*");
    		}
    		for(j=1;j<=2*i-1;j++){
    			printf("@");
    		}
    		for(j=1;j<=n-i;j++){
    			printf("*");
    		}
    		printf("\n");
    	}
    
    	return 0;
    }
    

    C++ :

    #include <iostream>
    using namespace std;
    
    int main(){
    	int i,j,n;
    	cin>>n;
    	for(i = 1;i <= n;i++){
    		for(j = 1;j <= n - i;j++) cout<<"*";
    		for(j = 1;j <= 2 * i - 1;j++) cout<<"@";
    		for(j = 1;j <= n - i;j++) cout<<"*";
    		cout<<endl;
    	}
    }
    
    

    Java :

    import java.util.Scanner;
    
    public class Main {
    	public static void main(String[] args) {	
    		Scanner sc= new Scanner(System.in);
    		int a = sc.nextInt();
    		sc.close();
    		for(int i=1;i<=a;i++) {
    			for(int j=1;j<=a-i;j++) {
    				System.out.print("*");
    			}
    			for(int k=1;k<=i*2-1;k++) {
    				System.out.print("@");
    			}
    			for(int j=1;j<=a-i;j++) {
    				System.out.print("*");
    			}
    			System.out.println();
    		}
    		
    	}
    }
    
    

    Python :

    n = int(input())
    for i in range(1, n + 1):
        for j in range(1, n - i + 1):
            print("*", end='')
        for j in range(1, 2 * i):
            print('@', end='')
        for j in range(1, n - i + 1):
            print("*", end='')
        print()
    
    • 1

    信息

    ID
    2414
    时间
    1000ms
    内存
    128MiB
    难度
    (无)
    标签
    递交数
    0
    已通过
    0
    上传者