1 条题解
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0
C :
#include<stdio.h> int main() { int n,m; scanf("%d %d",&n,&m); int i,j,a[n][m]; for(i=0;i<n;i++){ for(j=0;j<m;j++){ scanf("%d",&a[i][j]); } } for(i=1;i<n-1;i++){ for(j=1;j<m-1;j++){ if(a[i][j]>a[i-1][j]&&a[i][j]>a[i][j-1]&&a[i][j]>a[i][j+1]&&a[i][j]>a[i+1][j]){ printf("%d\n",a[i][j]); } } } return 0; }
C++ :
#include<bits/stdc++.h> using namespace std; int main(){ int i,n,m,j; int a[110][110]; cin>>n>>m; for(i=0;i<n;i++){ for(j=0;j<m;j++){ cin>>a[i][j]; } } for(i=1;i<n-1;i++){ for(j=1;j<m-1;j++){ if(a[i][j]>a[i-1][j]&&a[i][j]>a[i+1][j]&&a[i][j]>a[i][j-1]&&a[i][j]>a[i][j+1]){ cout<<a[i][j]<<endl; } } } }
Python :
n,m=list(map(int,input().split())) a=list() for i in range(n): a.append(list(map(int,input().split()))) for i in range(1,n-1): for j in range(1,n-1): if(a[i][j]>a[i-1][j] and a[i][j]>a[i][j+1] and a[i][j]>a[i+1][j] and a[i][j]>a[i][j-1]): print(a[i][j])
- 1
信息
- ID
- 2304
- 时间
- 1000ms
- 内存
- 16MiB
- 难度
- (无)
- 标签
- 递交数
- 0
- 已通过
- 0
- 上传者