1 条题解
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0
C++ :
#include<bits/stdc++.h> using namespace std; int main(){ int a[10][10]; int i,j,n; cin>>n; //赋初值 for(i = 0;i < n;i++){ for(j = 0;j < n;j++){ a[i][j] = 1; } } //赋0 for(i = 0;i <= n / 2;i++){ a[i][n/2 - i] = 0; a[i][n/2 + i] = 0; a[n - 1 - i][n/2 - i] = 0; a[n - 1 - i][n/2 + i] = 0; } a[n/2][n/2] = 0; for(i = 0;i < n;i++){ for(j = 0;j < n;j++){ cout<<setw(3)<<a[i][j]; } cout<<endl; } return 0; }
Python :
n = int(input()) a = [[1 for j in range(n)] for i in range(n)] # 先把中心点赋值为0 a[n // 2][n // 2] = 0 # 循环遍历,找出规律 for i in range(n): for j in range(n): if i + j == n // 2 or i - j == n // 2 or j - i == n // 2: a[i][j] = 0 if n == 5 and i + j == n + 1: a[i][j] = 0 if n == 7 and i + j == n + 2: a[i][j] = 0 if n == 9 and i + j == n + 3: a[i][j] = 0 # 打印输出 for i in range(n): for j in range(n): print('%3d' % a[i][j], end='') print()
- 1
信息
- ID
- 2247
- 时间
- 1000ms
- 内存
- 16MiB
- 难度
- (无)
- 标签
- 递交数
- 0
- 已通过
- 0
- 上传者