1 条题解
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0
C :
#include<stdio.h> void main() { int n; scanf("%d",&n); int a,b; for(a=1;a<=n/2+1;a++){ for(b=1;b<=a;b++){ printf("*"); } for(b=1;b<=2*(n/2-a)+2;b++){ printf(" "); } for(b=1;b<=a;b++){ printf("*"); } printf("\n"); } for(a=1;a<=n/2;a++){ for(b=1;b<=n/2-a+1;b++){ printf("*"); } for(b=1;b<=2*a;b++){ printf(" "); } for(b=1;b<=n/2-a+1;b++){ printf("*"); } printf("\n"); } }
C++ :
#include <bits/stdc++.h> using namespace std; int main(){ int n,i,j; cin>>n; n=n/2+1; for(i=1;i<=n;i++){ for(j=1;j<=i;j++){ cout<<"*"; } for(j=1;j<=(n-1)*2+1-2*i+1;j++){ cout<<" "; } for(j=1;j<=i;j++){ cout<<"*"; } cout<<endl; } for(i=n-1;i>=1;i--){ for(j=1;j<=i;j++){ cout<<"*"; } for(j=1;j<=(n-1)*2+1-2*i+1;j++){ cout<<" "; } for(j=1;j<=i;j++){ cout<<"*"; } cout<<endl; } }
Python :
n=int(input()) n1=n//2 for i in range(-n1,n1+1): if(i!=0): print("*"*(n1-abs(i)+1),end="") for j in range(1,abs(i)*2+1): print(" ",end="") print("*"*(n1-abs(i)+1),end="") print() else: print("*"*(n1+1)*2)
- 1
信息
- ID
- 2174
- 时间
- 1000ms
- 内存
- 16MiB
- 难度
- (无)
- 标签
- 递交数
- 0
- 已通过
- 0
- 上传者