1 条题解

  • 0
    @ 2023-6-11 12:16:27

    C :

    #include<stdio.h>
    int main()
    {
    	int n,i,j;
    	scanf("%d",&n);
    	int a[n][n];
    	for(i=0;i<n;i++){
    		a[i][0]=n-i;
    		for(j=1;j<=n;j++){
    			a[i][j]=a[i][j-1];
    		}
    		for(j=n-i;j<n;j++){
    			a[i][j]=a[i][j-1]+1; 
    		}
    	}
    	 for(i=0;i<n;i++){
    	 	for(j=0;j<n;j++){
    	 		printf("%3d",a[i][j]);
    		 }
    		 printf("\n");
    	 }
    return 0;
    }
    
    

    C++ :

    #include <bits/stdc++.h>
    using namespace std;
    
    int main(){
    	int a[10][10];
        int i,j,n;
        cin>>n;
         
        for (i = 0;i < n;i++){
            for (j = 0;j < n - i;j++){
                if (n < i + j){
    				a[i][j] = j + 2;
    				a[n - j - 1][n - i - 1] = j + 2;
    			}else{
    				a[i][j] = n - i;
    				a[n - j - 1][n - i - 1] = n - i;
    			}
            }
        }
         
        for (i = 0;i < n;i++){
            for (j = 0;j < n;j++){
                cout<<setw(3)<<a[i][j];
            }
            cout<<endl;
        }
    }
    

    Python :

    n = int(input())
    a = [[0 for j in range(n)] for i in range(n)]
    
    for i in range(n):
        # 先定好第一列数字
        a[i][0] = n - i
        for j in range(1, n - i):
            a[i][j] = a[i][j - 1]
        for j in range(n - i, n):
            a[i][j] = a[i][j - 1] + 1
    
    for i in range(n):
        for j in range(n):
            print('%3d' % a[i][j], end='')
        print()
    
    
    • 1

    信息

    ID
    2138
    时间
    1000ms
    内存
    16MiB
    难度
    (无)
    标签
    递交数
    0
    已通过
    0
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