1 条题解
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0
C :
#include<stdio.h> int main() { int n,i,j; scanf("%d",&n); int a[n][n]; for(i=0;i<n;i++){ a[i][0]=n-i; for(j=1;j<=n;j++){ a[i][j]=a[i][j-1]; } for(j=n-i;j<n;j++){ a[i][j]=a[i][j-1]+1; } } for(i=0;i<n;i++){ for(j=0;j<n;j++){ printf("%3d",a[i][j]); } printf("\n"); } return 0; }
C++ :
#include <bits/stdc++.h> using namespace std; int main(){ int a[10][10]; int i,j,n; cin>>n; for (i = 0;i < n;i++){ for (j = 0;j < n - i;j++){ if (n < i + j){ a[i][j] = j + 2; a[n - j - 1][n - i - 1] = j + 2; }else{ a[i][j] = n - i; a[n - j - 1][n - i - 1] = n - i; } } } for (i = 0;i < n;i++){ for (j = 0;j < n;j++){ cout<<setw(3)<<a[i][j]; } cout<<endl; } }
Python :
n = int(input()) a = [[0 for j in range(n)] for i in range(n)] for i in range(n): # 先定好第一列数字 a[i][0] = n - i for j in range(1, n - i): a[i][j] = a[i][j - 1] for j in range(n - i, n): a[i][j] = a[i][j - 1] + 1 for i in range(n): for j in range(n): print('%3d' % a[i][j], end='') print()
- 1
信息
- ID
- 2138
- 时间
- 1000ms
- 内存
- 16MiB
- 难度
- (无)
- 标签
- 递交数
- 0
- 已通过
- 0
- 上传者