1 条题解
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0
C :
#include<stdio.h> int main() { int n,i ,j; scanf("%d",&n); int a[n][n]; for(i=0;i<n;i++){ a[i][0]=1; for(j=1;j<=n-i-1;j++){ a[i][j]=a[i][j-1]+1; } for(j=n-i;j<n;j++){ a[i][j]=a[i][j-1]; } } for(i=0;i<n;i++){ for(j=0;j<n;j++){ printf("%3d",a[i][j]); } printf("\n"); } return 0; }
C++ :
#include<bits/stdc++.h> using namespace std; int a[110][110]; int main() { int n; cin>>n; for(int i=0;i<n;i++) { for(int j=i;j<n;j++) { for(int k=0;k<n-i;k++) { a[k][j]++; } } } for(int i=0;i<n;i++) { for(int j=0;j<n;j++) { cout<<setw(3)<<a[i][j]; } cout<<endl; } return 0; }
Python :
n = int(input()) a = [[0 for j in range(n)] for i in range(n)] for i in range(n): # 先定好第一列数字 a[i][0] = 1 for j in range(1, n - i): a[i][j] = a[i][j - 1] + 1 for j in range(n - i, n): a[i][j] = a[i][j - 1] for i in range(n): for j in range(n): print('%3d' % a[i][j], end='') print()
- 1
信息
- ID
- 2137
- 时间
- 1000ms
- 内存
- 16MiB
- 难度
- (无)
- 标签
- 递交数
- 0
- 已通过
- 0
- 上传者