1 条题解

  • 0
    @ 2023-6-11 12:15:52

    C :

    #include<stdio.h>
    int main()
    {
    	int n,i,j;
    	scanf("%d",&n);
    	int a[n][n];
    	for(i=0;i<n;i++){
    		a[i][0]=n;
    		for(j=1;j<=i;j++){
    			a[i][j]=a[i][j-1]-1;
    		}
    		for(j=i+1;j<n;j++){
    			a[i][j]=a[i][j-1];
    		}
         
    	}
    	for(i=0;i<n;i++){
    		for(j=0;j<n;j++){
    			printf("%3d",a[i][j]) ;
    		}
    		printf("\n");
    	}
    return 0;
    }
    

    C++ :

    #include <bits/stdc++.h>
    
    using namespace std;
    
    int main(){
    	 int n,a[423][423],i,j;
    	 cin>>n;
    	 for(i=1;i<=n;i++){
    	 	for(j=1;j<=n;j++){
    	 		if(i<j){
    	 			a[i][j]=n-i+1;
    			 }
    			 else{
    			 	a[i][j]=n-j+1;
    			 }
    		 }
    	 }
    	 for(i=1;i<=n;i++){
    	 	for(j=1;j<=n;j++){
    	 		cout<<setw(3)<<a[i][j];
    		 }
    		 cout<<endl;
    	 }
    } 
    

    Python :

    n = int(input())
    a = [[0 for j in range(n)] for i in range(n)]
    
    for i in range(n):
        # 先定好第一列数字
        a[i][0] = n
        for j in range(1, i + 1):
            a[i][j] = a[i][j - 1] - 1
        for j in range(i + 1, n):
            a[i][j] = a[i][j - 1]
    
    for i in range(n):
        for j in range(n):
            print('%3d' % a[i][j], end='')
        print()
    
    • 1

    信息

    ID
    2118
    时间
    1000ms
    内存
    16MiB
    难度
    (无)
    标签
    递交数
    0
    已通过
    0
    上传者