1 条题解

  • 0
    @ 2023-6-11 12:15:52

    C :

    #include<stdio.h>
    int main()
    {
    	int n,i,j;
    	scanf("%d",&n);
    	int a[n][n];
    	for(i=0;i<n;i++){
    		a[i][0]=n-i;
    		for(j=1;j<=i;j++){
    			a[i][j]=a[i][j-1];
    		}
    		for(j=i+1;j<n;j++){
    			a[i][j]=a[i][j-1]-1;
    		}
    	}
    	for(i=0;i<n;i++){
    		for(j=0;j<n;j++){
    			printf("%3d",a[i][j]) ;
    		}
    		printf("\n");
    	}
    return 0;
    }
    

    C++ :

    #include<iostream>
    #include<iomanip>
    using namespace std;
    
    int main(){
     	    int n;
                int a[11][11];
    	    cin>>n;
    			
                for (int i = 0; i < n; i++)
                {
                    for (int j = 0; j < n; j++)
                    {
                       
                        if (i >=j)
                        {
                            a[i][j] =n-i;
                        }
                        else
                        { 
                            a[i][j] = n-j;
                        }
                    }
                }
    
                for (int i = 0; i < n; i++)
                {
                 
                    for (int j = 0; j < n; j++)
                    {
                         cout<<setw(3)<<a[i][j];
                    }
                   cout<<endl;
                }
    
    
    }
    

    Python :

    n = int(input())
    a = [[0 for j in range(n)] for i in range(n)]
    
    for i in range(n):
        # 先定好第一列数字
        a[i][0] = n - i
        for j in range(1, i + 1):
            a[i][j] = a[i][j - 1]
        for j in range(i + 1, n):
            a[i][j] = a[i][j - 1] - 1
    
    for i in range(n):
        for j in range(n):
            print('%3d' % a[i][j], end='')
        print()
    
    
    • 1

    信息

    ID
    2117
    时间
    1000ms
    内存
    16MiB
    难度
    (无)
    标签
    递交数
    0
    已通过
    0
    上传者