1 条题解
-
0
C :
#include<stdio.h> int main(){ int n,i,j; scanf("%d",&n); int a[n][n]; for(i=0;i<n;i++){ a[i][0]=n-i; for(j=1;j<=i;j++){ a[i][j]=a[i][j-1]+1; } for(j=i+1;j<n;j++){ a[i][j]=a[i][j-1]-1; } } for(i=0;i<n;i++){ for(j=0;j<n;j++){ printf("%3d",a[i][j]); } printf("\n"); } return 0; }
C++ :
#include<iostream> #include<iomanip> using namespace std; int main(){ int n; int a[11][11]; cin>>n; for (int i = 0; i < n; i++) { for (int j = 0; j < n; j++) { if (j>=i) { a[i][j] =n-(j-i); } else { a[i][j] = n - (i - j); } } } for (int i = 0; i < n; i++) { for (int j = 0; j < n; j++) { cout<<setw(3)<<a[i][j]; } cout<<endl; } }
Python :
n = int(input()) a = [[0 for j in range(n)] for i in range(n)] for i in range(n): a[i][0] = n - i for j in range(1, i + 1): a[i][j] = a[i][j - 1] + 1 for j in range(i + 1, n): a[i][j] = a[i][j - 1] - 1 for i in range(n): for j in range(n): print('%3d' % a[i][j], end='') print()
- 1
信息
- ID
- 2115
- 时间
- 1000ms
- 内存
- 16MiB
- 难度
- (无)
- 标签
- 递交数
- 0
- 已通过
- 0
- 上传者