C :

#include<stdio.h>
int main()
{
	int a,b,i,j,n;
	scanf("%d%d%d",&n,&a,&b);
	for(i=1;i<=n;i++)
	{
		for(j=1;j<=n;j++)
		{
			if(i==a)
				printf("(%d,%d)",i,j);
		}
	
	}
	printf("\n");
	for(i=1;i<=n;i++)
	{
		for(j=1;j<=n;j++)
		{
			if(j==b)
				printf("(%d,%d)",i,j);
		}
	}
	printf("\n");
	for(i=1;i<=n;i++)
	{
		for(j=1;j<=n;j++)
		{
			if(j-i==b-a)
				printf("(%d,%d)",i,j);
		}
	}
	printf("\n");
		for(i=n;i>0;i--)
	{
		for(j=n;j>0;j--)
		{
			if(j+i==b+a)
				printf("(%d,%d)",i,j);
		}
	}
	printf("\n");
	return 0;

}

C++ :

#include<iostream>
#include<cmath>
using namespace std;
int main()
{
	int N,i,j;
	cin >> N >> i >> j;
	for(int k=1; k<=N; ++k)
		cout << "(" << i << "," << k << ")";
	cout << endl;
	for(int k=1; k<=N; ++k)
		cout << "(" << k << "," << j << ")";
	cout << endl;
	if(j-i>=0)
	{
		for(int k=1; k<=N-(int)fabs(j-i); ++k)
			cout << "(" << k << "," << (int)fabs(j-i)+k << ")";
	}
	else
	{
		for(int k=1; k<=N-(int)fabs(j-i); ++k)
			cout << "(" << (int)fabs(j-i)+k << "," << k << ")";
	}		 	 
	cout << endl;
	if((i+j)-(N+1)>=0)	
	{
		for(int k=N-(int)fabs((i+j)-(N+1)); k>=1; --k)
			cout << "(" << k+(int)fabs((i+j)-(N+1)) << "," << N+1-k << ")";
	}
	else
	{
		for(int k=N-(int)fabs((i+j)-(N+1)); k>=1; --k)
			cout << "(" << k << "," << N-(int)fabs((i+j)-(N+1))-k+1 << ")";
	}
	cout << endl;
	return 0;
}/*
 0  1  2  3
-1  0  1  2
-2 -1  0  1
-3 -2 -1  0 */

Java :

import java.util.Scanner;

public class Main {
	public static void main(String[] args) {
		// TODO Auto-generated method stub
		Scanner scanner = new Scanner(System.in);
		int N = scanner.nextInt(); // N*N格
		int i = scanner.nextInt(); // 第i行，格子(i，j)
		int j = scanner.nextInt(); // 第j列，格子(i，j)

		// (i，j)同一行上格子的位置
		for (int a = 1; a <= N; a++) {
			System.out.print("(" + i + "," + a + ")");
		}
		System.out.println();

		// (i,j)同一列上格子的位置
		for (int a = 1; a <= N; a++) {
			System.out.print("(" + a + "," + j + ")");
		}
		System.out.println();

		// 左上到右下对角线上的格子的位置
		// 从上往下，所以小到大，++
		for (int a = 1; a <= N; a++) {
			for (int b = 1; b <= N; b++) {
				if ((a - b) == (i - j)) {
					System.out.print("(" + a + "," + b + ")");
				}
			}
		}
		System.out.println();

		// 左下到右上对角线上的格子的位置
		// 从下往上，所以大到小，--
		for (int a = N; a >= 1; a--) {
			for (int b = N; b >= 1; b--) {
				if ((a + b) == (i + j)) {
					System.out.print("(" + a + "," + b + ")");
				}
			}
		}
	}
}